UpdatePanel无法直接弹出窗口的解决

发布时间：2014-06-13 来源：

   /// <summary>

    /// 自定义弹出窗口内容

    /// </summary>

    /// <param name="msg"></param>

    public static void AjaxShowWindows(string msg)

    {

        //myContext.Response.Write("<script>彈出窗口代碼(wondows.open(XXX));</script>");

        //注意彈出窗口的ID，最好使用隨機，否則只能彈出一次

        string script = "彈出窗口代碼(wondows.open(XXX));";

        ScriptManager.RegisterStartupScript(

            (System.Web.UI.Page)HttpContext.Current.CurrentHandler,

            typeof(System.Web.UI.Page), "ShowWindows", script, true);

    }

==========參考代碼===========

using System;
using System.Collections.Generic;
using System.Text;
using System.Web;
using System.Web.UI;

public class ShowMessage
{
/// <summary>
/// 自定义弹出窗口内容，不跳转
/// </summary>
/// <param name="page"></param>
/// <param name="msg"></param>
public static void Show(System.Web.UI.Page page, string msg)
{
page.ClientScript.RegisterStartupScript(page.GetType(),
"ShowMessage", "alert('" + msg + "');", true);
}
/// <summary>
/// 自定义弹出窗口内容，并跳转
/// </summary>
/// <param name="page"></param>
/// <param name="msg"></param>
/// <param name="returnUrl"></param>
public static void Show(System.Web.UI.Page page, string msg, string returnUrl)
{
page.ClientScript.RegisterStartupScript(page.GetType(),
"ShowMessage", "alert('" + msg + "

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